Getting character after / to capitalize

I've been scratching my head trying to get the following to detect any '/' that appears as a second character, then to capitalize the character immediately after it, which will be at position three.

If I use this as an example and capitalize the third character if it finds a 'c' at position two, then it works okay.

Code:

---

If oCtrl.Name = "txtVictim" Then
                        strTC = strConv(oCtrl.Text, vbProperCase)
                        Set oCC = ActiveDocument.SelectContentControlsByTag("Victim").Item(1)
                        oCC.Range.Text = strTC
                        For lngIndex = 1 To oCC.Range.Words.Count
                            If oCC.Range.Words(lngIndex).Characters(2) = "c" Then
                                oCC.Range.Words(lngIndex).Characters(3) = UCase(oCC.Range.Words(lngIndex).Characters(3))
                            End If
                        Next

---

If I change from 'c' to a '/' or char (47), then I get a Runtime error '5941' - The requested member of the collection does not exist on this line.

Code:

---

If oCC.Range.Words(lngIndex).Characters(2) = "/" Then

---

Because of the way 'words' are defined "/" is a word in its own right so cannot have two characters, hence the error.
If you want to capitalise after "/" then you will need to do it another way e.g.

Code:

---

Set oWrd = oCC.Range
    With oWrd.Find
        Do While .Execute(findText:="/")
            If oWrd.InRange(oCC.Range) Then
                oWrd.Next.Characters(1).Case = wdUpperCase
            End If
            oWrd.Collapse 0
        Loop
    End With

---

Thank you, Graham.

I would never have figured on a "/" being a word!

Is this the same for other characters such as "-", "#" and "&" etc.?

If in doubt use the following macro to list the words in the selected string in the immediate window

Code:

---

Sub Words()
Dim i As Integer
    For i = 1 To Selection.Words.Count
Debug.Print Selection.Words(i)
    Next i
End Sub

---

Lovely, thanks again Graham.