find last cell with formula

[lior03]

hello
i was trying to use johnske's article about finding the last row in a sheet containing formula using find or special cells methods.
is there another way to find the last cell in a sheet with a formula?
thanks

[Bob Phillips]

Why do you not want to use that method? The alternative is a long-winded check on every cell.

[lior03]

how do you fell about:
[VBA]
Cells.SpecialCells(xlCellTypeFormulas, xlCellTypeLastCell).Activate

[/VBA]

[Bob Phillips]

What do you mean? I have no feelings apart from it doesn't do what you asked originally.

[lior03]

hello
i found this two macros in johnske article.they both return the same result.why?
[VBA]
Sub Find_LastRowxlValues()
On Error GoTo Finish
MsgBox "Last row is row " & Cells.Find("*", _
SearchOrder:=xlByRows, LookIn:=xlValues, _
SearchDirection:=xlPrevious).EntireRow.row
Exit Sub
Finish:
MsgBox "No values found"
End Sub
Sub Find_LastRowxlFormulas()
On Error GoTo Finish
MsgBox "Last row is-" & Cells.Find("*", _
SearchOrder:=xlByRows, LookIn:=xlFormulas, _
SearchDirection:=xlPrevious).EntireRow.row, vbExclamation, "last cell with a 4mula:"
Exit Sub
Finish:
MsgBox "No formulas or values found - " & err.number
End Sub

[/VBA]
should'nt be any difference between a cell with a constant and a cell with a formula?what is ther lookin suppose to do?
thanks

[lior03]

my solution:
[VBA]
On Error GoTo Finish
MsgBox "Last formula row is-" & Cells.Find("=", _
SearchOrder:=xlByRows, LookIn:=xlFormulas, _
SearchDirection:=xlPrevious).EntireRow.row, vbExclamation, "last cell with a 4mula:"
Exit Sub
Finish:
MsgBox "No formulas or values found - " & err.number, vbCritical, "error"

[/VBA]