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Thread: Solved: Limit input to textbox

  1. #1

    Solved: Limit input to textbox

    Hi

    How can I limit the user input in a UF textbox to a certain range e.g.

    01 -> 31 (need the 0 in front of 1,2 3, etc as I want to auto tab to next TB once a valid 2 digit input is achieved) with message if incorrect input e.g 32

    Tried a few things but can't seem to crack it

    thanks for any help

    Jon

  2. #2
    Administrator
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    VBAX Grand Master mdmackillop's Avatar
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    [VBA]Private Sub TextBox1_BeforeUpdate(ByVal Cancel As MSForms.ReturnBoolean)
    If IsNumeric(TextBox1) And Len(TextBox1) = 2 Then
    'do nothing
    Else
    Cancel = True
    MsgBox "Please enter 2 digit number"
    TextBox1 = ""
    End If
    End Sub[/VBA]
    MVP (Excel 2008-2010)

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  3. #3
    VBAX Mentor MaximS's Avatar
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    try to add below code to your User Form (change TextBox1 to name of your textbox):

    [VBA]
    Private Sub TextBox1_Exit(ByVal Cancel As MSForms.ReturnBoolean)
    Dim temp As String, err As String

    If Len(Me.TextBox1.Text) = 1 And CInt(Me.TextBox1.Text) > 0 Then
    temp = "0" & Me.TextBox1.Text
    Me.TextBox1.Text = temp
    Else
    If CInt(Me.TextBox1.Text) >= 0 Then
    If CInt(Me.TextBox1.Text) > 32 Then
    err = MsgBox("Please enter number between 0 and 32", _
    vbCritical + vbOKOnly, "Wrong Input")
    End If
    Else
    err = MsgBox("Please enter number between 0 and 32", _
    vbCritical + vbOKOnly, "Wrong Input")
    End If
    End If

    End Sub
    [/VBA]

  4. #4
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    VP-Knowledge Base VBAX Grand Master mdmackillop's Avatar
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    I forgot about the 31 limit
    [VBA]
    Private Sub TextBox1_BeforeUpdate(ByVal Cancel As MSForms.ReturnBoolean)
    If IsNumeric(TextBox1) And Len(TextBox1) = 2 And _
    CInt(TextBox1) > 0 And CInt(TextBox1) < 31 Then
    'do nothing
    Else
    Cancel = True
    MsgBox "Please enter 2 digit number between 1 & 31"
    TextBox1 = ""
    End If
    End Sub

    [/VBA]
    MVP (Excel 2008-2010)

    Post a workbook with sample data and layout if you want a quicker solution.


    To help indent your macros try Smart Indent

    Please remember to mark threads 'Solved'

  5. #5
    Mac Moderator VBAX Guru mikerickson's Avatar
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    [VBA]Private Sub TextBox1_KeyPress(ByVal KeyAscii As MSForms.ReturnInteger)
    If Len(TextBox1.Text) = 0 Then
    Select Case Chr(KeyAscii)
    Case Is = "1", "0", "2", "3"
    Case Else
    KeyAscii = 0
    End Select
    Else
    Select Case Chr(KeyAscii)
    Case Is = "1", "0", "2", "3", "4", "5", "6", "7", "8", "9"
    If 0 < Val(TextBox1.Text & Chr(KeyAscii)) And Val(TextBox1.Text & Chr(KeyAscii)) < 33 Then
    TextBox1.Text = TextBox1.Text & Chr(KeyAscii)
    KeyAscii = 0
    TextBox2.SetFocus
    Else
    KeyAscii = 0
    End If
    Case Else
    KeyAscii = 0
    End Select
    End If
    End Sub[/VBA]

  6. #6
    Thanks Guys,

    Mike, I already have a 'change' sub for the textbox which activates the next textbox and label - is there anyway to incorporate this - your code works but doesn't light up the next TB

    Max - couldn't get your code to work - fails on the first if statement

    thanks

  7. #7
    Mac Moderator VBAX Guru mikerickson's Avatar
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    I'd need to see the existing Change event to see how to incorperate it. But if that Change event handles the "go to next textbox" part of your requirements, try removing [VBA]TextBox2.SetFocus[/VBA] from my code.

  8. #8
    Yep - removing it from your code does allow it to work.

    Just one slight problem - it does allow 32 to be entered

    I will try to work out how your code handles this set of numbers so I can apply it to the next set which will be 01 through to 12

    thanks

  9. #9
    I see the end number is set to 33 - think if I chanfge to 32 it will work ok

    thanks again

    Jon

  10. #10
    VBAX Mentor MaximS's Avatar
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    Hi blackie,

    the only reason i see why it might not work is fact you testing that code with nothing typed in the text box.

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