We need to use character substitution then - i will replace all " / " with "!@#" and then replace them back when we are done. Check it out!
Option Explicit
Sub splitEmUp()
Dim splitter() As String 'this is storage space for the split function
Dim i As Integer ' main-loop for counter "which cell we are on"
Dim j As Integer ' splitter for-loop counter "which section of the split are we on"
Range("b2").Activate 'starting in cell b2 because row 1 is headers and category is located in the B column
For i = 0 To 50 'from beginning to end i=0 means b2, i=1 means b3
ActiveCell.Offset(i, 0).Value = Replace(ActiveCell.Offset(i, 0).Value, " / ", "!@#")
splitter = Split(ActiveCell.Offset(i, 0), "/") 'split the cell based on / and store it in splitter
If (UBound(splitter)) > 0 Then 'if a split occurred
ActiveCell.Offset(i, 0).Value = "" 'set the activecell to blank
Debug.Print i
ActiveCell.Offset(i + 1, 0).EntireRow.Insert shift:=xlDown, copyorigin:=xlFormatFromLeftOrAbove 'insert a new row and shift everything down
ActiveCell.Offset(i + 1, 0).Value = splitter(0) 'initialize the "Down" cells
ActiveCell.Offset(i + 1, 0).Value = Replace(ActiveCell.Offset(i + 1, 0).Value, "!@#", " / ")
For j = 1 To UBound(splitter)
ActiveCell.Offset(i + j + 1).EntireRow.Insert shift:=xlDown, copyorigin:=xlFormatFromLeftOrAbove 'create another row if it needs to
ActiveCell.Offset(i + (j + 1), 0).Value = ActiveCell.Offset(i + j).Value & "/" & splitter(j) 'fill out the new row
ActiveCell.Offset(i + (j + 1), 0).Value = Replace(ActiveCell.Offset(i + (j + 1), 0).Value, "!@#", " / ")
Next
i = i + UBound(splitter) + 1 'need to step I past the new cells
ReDim splitter(0)
Erase splitter 'erase and eliminate splitter to avoid carry over.
End If
Next
End Sub