Solved with 3 answers.
the =countif(d9:d50,"*"&"p"&"*") provided the best results because it counted number of blocks with a "p" in them and that the answer I needed.
the
=SUMPRODUCT((LEN(D9:D50)-LEN(SUBSTITUTE(UPPER(D9:D50),"P",""))
Counted all occurances of "P" in the Blocks not exactly what I needed but close. Also after the =sum formula is entered you must "Ctrl+Shift+Enter" to get it to work. MS KB 213889
I did not try the VB solution because I new at VB.
Thanks for all your help
Mike in Wisconsin