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Thread: SOLVED: Function needed for business days

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  1. 07-23-2004, 06:50 AM #7
    babsc01
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    Abulafia...the function you pointed me to works great. I think this thread can be considered SOLVED. But, the user will have to create a new table called tblHolidays (below) within the same DB as the code for it to work. Easy enough to do. THANKS!!!!

    1/1/20015/28/20017/4/20019/3/200111/22/200111/23/200112/25/20011/1/20025/27/20027/4/20029/2/200211/28/200211/29/200212/25/2002
    1/1/20035/26/20037/4/20039/1/200311/27/200311/28/200312/25/20031/1/20045/31/20047/5/20049/6/200411/25/200411/26/200412/24/200412/31/2004
    Last edited by TonyJollans; 07-23-2004 at 07:02 AM. Reason: Break long string
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